Question

A rigid diatomic ideal gas undergoes an adiabatic process at room temperature,. The relation between temperature and volume of this process is $T{V}^x$ = constant, then $x$ is :

• A. $\frac{5}{3}$
• B. $\frac{2}{5}$
• C. $\frac{2}{3}$
• D. $\frac{3}{5}$

Answer 1

Answer: (B)

$\frac{2}{5}$

For adiabatic process :$T{V}^{\gamma -1}=$ constant
For diatomic process : $\gamma -1=\frac{7}{5}-1$
$\therefore x=\frac{2}{5}$