Question

A ring is rolling without slipping. Its energy of translation is $E$. its total kinetic energy will be :-

• A. $E$
• B. $2E$
• C. $3E$
• D. $4E$

Answer 1

The correct option is B $2E$

$TE=\frac{1}{2}m{v}^2+\frac{1}{2}{I}_{cm}{w}^2$

$\Rightarrow TE=\frac{1}{2}m{v}^2+\frac{1}{2}\times m{R}^2\times \frac{v^2}{R^2}$

$E+E$

$TE=2E$

Hence,

option $\left(B\right)$ is correct answer.