wiz-icon
MyQuestionIcon
MyQuestionIcon
11
You visited us 11 times! Enjoying our articles? Unlock Full Access!
Question

A ring is rotating with an angular acceleration given by α=4t332t2, where t is time. Find the equation of angular speed ω if the ring starts from rest.

A
t4t32
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
t3t
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
t42t3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
12t23t
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A t4t32
We know that angular acceleration (α) is the time rate of change of angular velocity (ω)

It is given the angular acceleration is,
α=4t332t2

and hence for finding angular velocity we integrate (α)

α=dωdtω=α dt
ω=(4t332t2)dt
=4t4432t33+c
As it starts from rest t=0, ω=0c=0
So,
ω=t4t32

Hence option A is the correct answer.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relative
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon