Magnetic Field Due to a Straight Current Carrying Conductor
A ring of rad...
Question
A ring of radius R is uniformly charged, and it carries a total charge Q. At a point which is at a distance of R√3 from the center and lying on the axis of the ring, electric field due to half part is E1 & due to the other half part is E2, then
A
E1E2=√31
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
E1E2=1√3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
E1E2=21
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
E1E2=1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is DE1E2=1
Using concept of symmetry, we can say that, ∣∣∣−→E1∣∣∣=∣∣∣−→E2∣∣∣ ∴ Option d is correct.