A ring with a uniform charge Q and radius R, is placed in the yz plane with its centre at the origin. Then :
A
The field at the origin is zero
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B
The potential at the origin is kQR
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C
The field at the point (x, 0, 0) is kQx2
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D
The field at the point (x, 0, 0) is kQR2+x2
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Solution
The correct options are A The field at the origin is zero B The potential at the origin is kQR The electric field due to the ring at a point p on the axis of ring is E=kQz(z2+R2)3/2 At center, z=0,E=0. Thus the electric field at the origin is zero. As E=−dVdz, the electric potential due to the ring at a point p on the axis of ring is V=kQ√z2+R2 At center, z=0,V=kQ/R