Question

A road is passing through a hilly area with a horizontal curve. If the superelevation provided is 1 in 10 and the coefficient of lateral friction is 0.16, minimum radius of the horizontal curve which the vehicles can negotiate safely at a speed of 40 kmph in metres is

• A. 48.45

Answer 1

The correct option is A 48.45
$e=\frac{1}{10}=0.1$

$f=0.16$

$V=40kmph$

Now,
$e+f=\frac{v^2}{gR}$

If V is in km/hr, then

$\Rightarrow e+f=\frac{V^2}{127R}$

$\Rightarrow 0.1+0.16=\frac{{\left(40\right)}^2}{127R}$

Solving, we get

$R=48.45m$