The design speed for a National Highway is 100 kmph. If the maximum permissible superelevation is 0.10 and the coefficient of lateral friction is 0.15, the ruling minimum radius of horizontal curve on the highway should be

260 m

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410 m

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380 m

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315 m

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Solution

The correct option is D $315 m$
The ruling minimum radius of horizontal curve is given by
$R_{m i n} = \frac{V^{2}}{127 (e + f)}$

$= \frac{(100)^{2}}{127 (0.10 + 0.15)}$

$= 314.96 m ≃ 315 m$

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The design speed for a National Highway is 100 kmph. If the maximum permissible superelevation is 0.10 and the coefficient of lateral friction is 0.15, the ruling minimum radius of horizontal curve on the highway should be

The correct option is D 315mThe ruling minimum radius of horizontal curve is given by Rmin=V2127(e+f) =(100)2127(0.10+0.15) =314.96m≃315m

The correct option is D $315 m$
The ruling minimum radius of horizontal curve is given by
$R_{m i n} = \frac{V^{2}}{127 (e + f)}$

$= \frac{(100)^{2}}{127 (0.10 + 0.15)}$

$= 314.96 m ≃ 315 m$