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Question

A road roller was used for levelling a road of width 2 m. It was observed that, the road roller required 25 complete revolutions to level the entire road. If the radius and the length of the roller is 7 m and 2 m respectively, then length of the road is ____. [Take π = 3.14].


A

1200 m

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B

2100 m

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C

1100 m

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D

1234 m

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Solution

The correct option is C

1100 m


Given, Radius of Cylinder, r=7 m
length of roller, h=2 m
Width of road, B=2 m
Length of road be L
Number of revolution taken = 25

Roller rolls on its curved surface area.
Surface area of = CSA of cylinder
one revolution
=2πrh=2×227×7×2=88 m2

Total area covered in 25 revolution =25×88=2200 m2

This area will be equal to the area of the road levelled

Area of road = L×B=2200L×2=2200L=1100 m

Length of the level road is 1100 m.


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