A road runs midway between two parallel rows of buildings. A motorist moving with a speed of $36 k m / h o u r$ sounds the horn. He hears the echo one second after he has sounded the horn. The distance between the $2$ rows of buildings is (Velocity of sound is $330 m / s$ )

300 m

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150 m

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1080 m

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330 m

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Solution

The correct option is D $330 m$
Distance of person standing midway between the two roads from building $= \frac{2 v}{t} = \frac{2 \times 330}{1} = 660 m$

$∴$ Distance between two roads $= \frac{d}{2} = 330 m$

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A road runs midway between two parallel rows of buildings. A motorist moving with a speed of 36km/hour sounds the horn. He hears the echo one second after he has sounded the horn. The distance between the 2 rows of buildings is (Velocity of sound is 330m/s)

The correct option is D 330mDistance of person standing midway between the two roads from building =2vt=2×3301=660 m∴ Distance between two roads =d2=330 m

A road runs midway between two parallel rows of buildings. A motorist moving with a speed of $36 k m / h o u r$ sounds the horn. He hears the echo one second after he has sounded the horn. The distance between the $2$ rows of buildings is (Velocity of sound is $330 m / s$ )

The correct option is D $330 m$
Distance of person standing midway between the two roads from building $= \frac{2 v}{t} = \frac{2 \times 330}{1} = 660 m$

$∴$ Distance between two roads $= \frac{d}{2} = 330 m$