Question

A rocket is fired and ascends with constant vertical acceleration of $10m/s^2$ for 1 minute. Its fuel is exhausted and it continues as a free particle.The maximum altitude reached is ($g=10m/s^2$)

• A. 18 km
• B. 36 km
• C. 72 km
• D. 108km

Answer 1

Answer: (B)

36 km

For $1$ minute, distance, $d$ travelled is:
$d=h{t}^0+\frac{1}{2}a{t}^2=\frac{1}{2}\times 10\times (60{)}^2=\frac{36000}{2}=18000mt$
$v=u+at=10\times 60=600m/s$

Now, for max $m$ height:
$v_1^2=4_1^2-2gs(v_1=v)$
$\Rightarrow s=\frac{(600{)}^2}{2g}=\frac{600\times 600}{2\times 10}=18000mt$
$\Rightarrow$ Total attitude $=d+s=18000+18000$
$=36000m$
$=36Km$