Question

A rocket is in the form of a right circular cylinder closed at the lower end and surmounted by a cone with the same radius as that of the cylinder. The diameter and height of the cylinder are $6$ cm and $12$ cm, respectively. If the the slant height of the conical portion is $5$ cm, then the total surface area and volume of the rocket $[Use\pi =3.14]$ is $301.44c{m}^2,377.1c{m}^3$ respectively
If true then enter $1$ and if false then enter $0$

Answer 1

Curved surface area of cylinder $=2\pi \left(3\right)\left(12\right)=72\pi c{m}^2$
Area of circle $=\pi 3^2=9\pi c{m}^2$
curved surface area of cone $=\pi \left(3\right)\left(5\right)=15\pi c{m}^2$
Total surface area of rocket $=96\pi =301.7c{m}^2$
$\Rightarrow h^2+3^2=5^2$

$\Rightarrow h=4$
Volume of cylinder $=\pi 3^2\left(12\right)=108\pi c{m}^3$
Volume of cone $=\frac{1}{3}\times \pi 3^2\left(4\right)=12\pi c{m}^3$
Volume of rocket $=(108+12)\pi =120\pi =377.14c{m}^3$