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Question

A rod of length 1000 rom and coefficient of linear expansion α=104; 10-4 per degree celsius is placed inhorizontal smooth surface symmetrically between fixed walls separated by 1001 rnm. The Young'smodulus of rod is 1011N/m2 . If the temperatore is increased by 20oC, then the stress developed in the rod is ( in N/m2)

A
105
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B
108
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C
107
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D
106
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Solution

The correct option is B 108
Δl due to temperature rise
=lαΔΘ
=(1000)(104)(20)
=2mm
But I mm is allowed (l000mm to 1001 mm)
Δle=1mm
Strees=Y×Strain
=(1011)(1mm1000mm)
=108N/m2

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