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Standard VIII

Mathematics

Total Surface Area of a Cuboid

A room 5 m ...

Question

A room $5$ m long, $4.5$ m wide and $3.6$ m high has one door $1.5$ m by $2.4$ m and two windows, each $1$ m by $0.75$ m. then the cost of distempering its walls at the rate of Rs 4.50 per $m^{2}$ is Rs 284.85

If true then enter $1$ else 0

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Solution

Area for distempering = 2(lh+bh)-(1.5 $\times$ 2.4)-2(1 $\times$ 0.75)
= 2(5 $\times$ 3.6+4.5 $\times$ 3.6)-5.1
= 63.3 $m^{2}$

Cost = 63.3 $\times$ 4.5
= 284.85 Rs

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A room 5 m long, 4.5 m wide and 3.6 m high has one door 1.5 m by 2.4 m and two windows, each 1 m by 0.75 m. then the cost of distempering its walls at the rate of Rs 4.50 per m2 is Rs 284.85If true then enter 1 else 0

Area for distempering = 2(lh+bh)-(1.5×2.4)-2(1×0.75) = 2(5×3.6+4.5×3.6)-5.1 = 63.3 m2Cost = 63.3×4.5 = 284.85 Rs

A room $5$ m long, $4.5$ m wide and $3.6$ m high has one door $1.5$ m by $2.4$ m and two windows, each $1$ m by $0.75$ m. then the cost of distempering its walls at the rate of Rs 4.50 per $m^{2}$ is Rs 284.85

If true then enter $1$ else 0

Area for distempering = 2(lh+bh)-(1.5 $\times$ 2.4)-2(1 $\times$ 0.75)
= 2(5 $\times$ 3.6+4.5 $\times$ 3.6)-5.1
= 63.3 $m^{2}$

Cost = 63.3 $\times$ 4.5
= 284.85 Rs