CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

A room is $$4.8 \ m$$ long, $$3.6 \ m$$ broad and $$2 \ m$$ high. Find the cost of laying tiles on its floor and its four walls at the rate of $$ Rs. 100/m^2$$.


Solution

Formula for Area is given by $$2h(l + b)$$
We have, $$l = 4.8m; b = 3.6m; h = 2m$$
$$\therefore$$ , Area = $$2$$ x $$2$$ $$[ 4.8 + 3.6]$$= $$33.6m^2$$
Therefore, the area of four walls is $$33.6m^2$$
Now, we have find the area of the floor = ($$l$$ x $$b$$) = ( $$4.8$$ x $$3.6$$ ) = $$17.28 m^2$$
Thus, area of floor + area of $$4$$ walls = $$17.28m^2 + 33.6m^2$$ = $$50.88m^2$$
Thus, the cost of laying tiles on its floor and its four walls at the rate of Rs.  $$100/m$$  = $$50.88$$ x $$100$$= $$Rs \ 5088 $$

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image