Question

# A room is $$4.8 \ m$$ long, $$3.6 \ m$$ broad and $$2 \ m$$ high. Find the cost of laying tiles on its floor and its four walls at the rate of $$Rs. 100/m^2$$.

Solution

## Formula for Area is given by $$2h(l + b)$$ We have, $$l = 4.8m; b = 3.6m; h = 2m$$$$\therefore$$ , Area = $$2$$ x $$2$$ $$[ 4.8 + 3.6]$$= $$33.6m^2$$ Therefore, the area of four walls is $$33.6m^2$$ Now, we have find the area of the floor = ($$l$$ x $$b$$) = ( $$4.8$$ x $$3.6$$ ) = $$17.28 m^2$$ Thus, area of floor + area of $$4$$ walls = $$17.28m^2 + 33.6m^2$$ = $$50.88m^2$$ Thus, the cost of laying tiles on its floor and its four walls at the rate of Rs.  $$100/m$$  = $$50.88$$ x $$100$$= $$Rs \ 5088$$Mathematics

Suggest Corrections

0

Similar questions
View More

People also searched for
View More