Question

A room is $4.8m$ long, $3.6m$ broad and $2m$ high. Find the cost of laying tiles on its floor and its four walls at the rate of $Rs.100/m^2$.

Answer 1

Formula for Area is given by $2h(l+b)$
We have, $l=4.8m;b=3.6m;h=2m$
$\therefore$ , Area = $2$ x $2$ $[4.8+3.6]$= $33.6m^2$
Therefore, the area of four walls is $33.6m^2$
Now, we have find the area of the floor = ($l$ x $b$) = ( $4.8$ x $3.6$ ) = $17.28m^2$
Thus, area of floor + area of $4$ walls = $17.28m^2+33.6m^2$ = $50.88m^2$
Thus, the cost of laying tiles on its floor and its four walls at the rate of Rs. $100/m$ = $50.88$ x $100$= $Rs5088$