A room is 9.68 m long and 6.2 m wide. Its floor is to be covered with rectangular tiles of size 22 cm by 10 cm. Find the total cost of the tiles at the rate of Rs 2.50 per tile.

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Solution

We have,
Length of the floor of the room = 9.68 m
Breadth of the floor of the room = 6.2 m
Area of the floor = 9.68 m x 6.2 m = 60.016 m²
Length of the tile = 22 cm
Breadth of the tile = 10 cm
Area of one tile = 22 cm x 10 cm = 220 cm² = 0.022 m² [Since 1 m² = 10000 cm²]
Thus,
Number of tiles = $\frac{60.016 m^{2}}{0.022 m^{2}} = 2728$
Cost of one tile = Rs. 2.50
Total cost = Number of tiles x Cost of one tile
= Rs. (2728 x 2.50) = Rs. 6820

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