Question

A room is 8 m long and 6 m wide. Its floor is to be covered with rectangular tiles of size 25 cm by 20 cm. How many tiles will be required? Find the cost of these tiles at ₹25 per tile.

Answer 1

We have,
Length of the room = 8 m = 800 cm,
Breadth of the room = 6 m = 600 cm,
Length of the tile = 25 cm and
Breadth of the tile = 20 cm

$$\begin{gathered} \mathrm{Now}, \\ \mathrm{The}\mathrm{number}\mathrm{of}\mathrm{the}\mathrm{tiles}\mathrm{required}=\frac{\mathrm{Area}\mathrm{of}\mathrm{the}\mathrm{floor}\mathrm{of}\mathrm{the}\mathrm{room}}{\mathrm{Area}\mathrm{of}\mathrm{a}\mathrm{tile}} \\ =\frac{\mathrm{Length}\mathrm{of}\mathrm{the}\mathrm{room}\times \mathrm{Breadth}\mathrm{of}\mathrm{the}\mathrm{room}}{\mathrm{Length}\mathrm{of}\mathrm{the}\mathrm{tile}\times \mathrm{Breadth}\mathrm{of}\mathrm{the}\mathrm{tile}} \\ =\frac{800\times 600}{25\times 20} \\ =960 \\ \mathrm{So},\mathrm{the}\mathrm{number}\mathrm{of}\mathrm{tiles}\mathrm{required}\mathrm{to}\mathrm{cover}\mathrm{the}\mathrm{floor}\mathrm{of}\mathrm{the}\mathrm{room}\mathrm{is}960. \\ \mathrm{Also}, \\ \mathrm{Since},\mathrm{the}\mathrm{cost}\mathrm{of}1\mathrm{tile}=₹25 \\ \mathrm{So},\mathrm{the}\mathrm{cost}\mathrm{of}\mathrm{the}960\mathrm{tiles}\mathrm{such}\mathrm{tiles}=25\times 960=₹24,000. \end{gathered}$$