Question

A rope of length 4 m having mass density 1.5 kg/m lying on a horizontal frictionless surface is pulled at one end by a force of 12 N. What is the tension in newtons in the rope at a point 1.6 m from the other end?

Answer 1

As shown in figure the mass of the rope: m = 4 $\times$ 1.5 = 6 kg
Acceleration: $a=12/6=2{\text{m/s}}^2$

Mass of part 1 as shown in figure $m_1=1.6\times 1.5=2.4\text{kg}$
$T=m_{1}a=2.4\times 2=4.8\text{N}$