A rope of mass 5kg is moving vertically with an upward force of 100N acting at the upper end and a downward force of 70N acting at the lower end. The tension at the midpoint of the rope is
(Take g=10m/s2)
A
100N
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B
85N
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C
75N
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D
105N
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Solution
The correct option is B85N
FBD of the rope will be
Using FBD, we can write 70+5×g−100=5×a⟹a=4m/s2
Hence rope will be accelerating downwards with an acceleration of 4m/s2
Let T be the tension at the mid-point of the rope
Now, draw the FBD of upper half of this rope