# Tension in a String

## Trending Questions

**Q.**Find the ratio of tensions T1 to T2 for the figure shown.

- 8:5
- 5:8
- 3:4
- 4:3

**Q.**For the system shown in the figure, if F2 and F3 are forces acting on the masses m2 and m3 respectively, then the correct relation between the forces is (Assume that the blocks are connected by inextensible strings and the surface is frictionless)

- F3=F1+F2
- F3=m1F1m1+m2+m3
- F3=m2F1m1+m2+m3
- F3=m3F1m1+m2+m3

**Q.**In the following figure the masses of the blocks A and B are the same and each equal to m. The tensions in the strings OA and AB are T2 and T1 respectively. The system is in equilibrium with a constant horizontal force mg on B. Then T2 is:

- mg
- √2mg
- √3mg
- √5mg

**Q.**

Find the tension in the string and the acceleration of the blocks?

T = 3 N , a= 3m/s2

T = 4 N , a= 4m/s2

T = 6 N , a= 2m/s2

None of these

**Q.**Find the acceleration of the system shown in the figure.

- g7
- g3
- 2g5
- 2g7

**Q.**Two blocks are connected with a string and the system is connected to another string which is fixed at the centre of a circular table as shown in the figure. The table is rotating with an angular speed of ω about its centre. Find the tension in the string which is fixed at the centre.

- mω2r1
- mω2r2
- mω2(r1+r2)
- mω2(r1−r2)

**Q.**In the figure the block of mass M is at rest on the floor. The acceleration with which a monkey of mass m should climb up along the rope of negligible mass so as to lift the block from the floor is,

- =(Mm−1)g
- > (Mm−1)g
- =Mmg
- > Mmg

**Q.**If F=120 N which is parallel to the inclined plane, find the tension T2 in string. (g=10 m/s2)

- 15 N
- 30 N
- 45 N
- 60 N

**Q.**In the figure shown, the 12 kg body pulled by a string with an acceleration a=2.2 m/s2. The tension T1 and T2 will be respectively

(Take g=9.8 m/s2)

- 200 N, 80 N
- 240 N, 90 N
- 240 N, 96 N
- 260 N, 96 N

**Q.**Three equal weights A, B and C of mass 2 kg each are hanging on a string passing over a fixed frictionless pulley as shown in the figure. The tension in the string connecting weights B and C is

- Zero
- 13 N
- 3.3 N
- 19.6 N

**Q.**A body of mass 5 kg is suspended by the strings making angles 60o and 30o with the horizontal as shown in the figure. Find the tension in the strings. (g=10 m/s2 )

- T1=25 N & T2=25 N
- T1=25√3 N & T2=25 N
- T1=25 N & T2=25√3 N
- T1=25√3 N & T2=25√3 N

**Q.**Two blocks of masses 6 kg and 4 kg connected by a rope of mass 2 kg are resting on a frictionless floor as shown in the figure. If a constant force 60 N is applied to the 6 kg block, find the tension in the rope at points A, B and C. B is at the mid-point and points A and C are at the ends. Assume that the mass of the rope is uniformly distributed along its length.

- 30 N, 25 N, 20 N respectively
- 20 N, 20 N, 30 N respectively
- 30 N, 20 N, 25 N respectively
- None of the above

**Q.**Three blocks of mass 2 kg, 3 kg and 5 kg are connected to each other with light string and are then placed on a frictionless surface as shown in the figure. The system is pulled by a force of 10 N, tension T1 is equal to

- 1 N
- 5 N
- 8 N
- 10 N

**Q.**In both the cases, block & monkey are at the same horizontal level. In both the cases, monkey climbs the rope. In case-1 rope remains vertical & in case-2 rope swings during motion. t1 & t2 are times taken by monkeys to reach the pulley in case-1 & case-2 respectively. In both cases, monkey applies the same force on the rope.

- t1=t2
- t1<t2
- In case-2, block reaches the pulley earlier than monkey
- In case-1, monkey reaches the pulley earlier than block

**Q.**In the figure shown, find the tension T1 (in N) in the string. Assume the strings to be inextensible and pulley frictionless.

- 2 g
- 3 g
- 2.5 g
- 4 g

**Q.**Find F such that the 2 kg body goes up with an acceleration of 2 m/s2.

Take (g=10 m/s2)

- 10 N
- 20 N
- 25 N
- 30 N

**Q.**A string of length 1 m is fixed at one end and carries a mass of 100 g at the other end. The string makes (2/π) revolutions per second around vertical axis through the fixed end. What is the tension in the string :-

- 1.6 N
- 0.8 N
- 3.2 N
- 2.4 N

**Q.**A mass m is suspended by a rope from a rigid support at P as shown in the figure. Another rope is tied at the end Q which is pulled horizontally with a force F. If the rope PQ makes angle θ with the vertical, then tension in the string PQ is

- Fsinθ
- Fsinθ
- Fcosθ
- Fcosθ

**Q.**In two pulley - particle figures (i) and (ii), the acceleration and force imparted by the string on the pulley and tension in the strings are, (a1, a2), (N1, N2), and (T1, T2) respectively. Ignoring friction in all contacting surfaces, which of the following relations is true?

- a1a2=1
- T1T2<1
- N1N2>1
- a1a2<1

**Q.**A steel ball is suspended from the ceiling of an accelerating carriage by means of two cords A and B. Determine the acceleration a ( in m/s2) of the carriage which will cause the tension in A to be twice that in B

- g√3
- g√3
- 3√3g
- g3√3

**Q.**A ball of mass 1 kg hangs in equilibrium from two strings OA and OB as shown in the figure. What are the tensions in strings OA and OB? (Take g=10 ms−2)

- 5 N, zero
- zero, N
- 5 N, 5√3 N
- 5√3 N, 5 N

**Q.**In the figure shown, all the blocks are of equal mass of 10 kg and F=300 N. Find the tension in the string, TBC. Assume all surface to be smooth and g=10 m/s2.

- 100 N
- 150 N
- 200 N
- 250 N

**Q.**Two blocks of masses m and 2m are placed on triangular wedge by means of a massless inextensible string over a frictionless fixed pulley. Surface of contact between the masses and wedge is frictionless and wedge makes 45∘ with horizontal on both sides as shown in figure. The tensions in the string (T) is

- 4mg3√2 N
- 2mg3√2 N
- mg3√2 N
- 3mg√2 N

**Q.**Two beads A and B of equal mass m are connected by a light rod, which acts as a chord for the ring. They are constrained to move on the frictionless ring in a vertical plane. The beads are released from rest as shown in figure. The tension in the chord just after release will be:

- mg4

- √2 mg
- mg2

- mg√2

**Q.**If force, F=48 N is acting on the system as shown in figure, find the tension in string. All surfaces are smooth.

(Take g=10 m/s2)

- 12 N
- 9.6 N
- 8.4 N
- 5.6 N

**Q.**Three blocks A, B and C weighing 1 kg, 8 kg and 27 kg respectively are connected as shown in the figure, with an inextensible string and are moving on a smooth surface. If tension T3 is equal to 36 N, then tension T2 is

- 18 N
- 9 N
- 3.375 N
- 1.25 N

**Q.**A particle is suspended by thread of length l from a fixed point. If it is launched from the bottom with a horizontal speed of v=√5gl, then tension in the thread when the particle is at the topmost point

- T=mg
- T=0
- T=5mg
- T=6mg

**Q.**In the figure shown, all the blocks are of equal mass of 10 kg and F=300 N. Find the tension in the string TAB. Assume all surface to be smooth and g=10 m/s2.

- 100 N
- 150 N
- 200 N
- 250 N

**Q.**Two containers of sand are arranged like the block as shown in figure. The containers alone have negligible mass; the sand in these containers has a total mass Mtot; the sand in the hanging container H has mass m.

To measure the magnitude of the acceleration of the system, a large number of experiments have been carried out where m varies from experiment to experiment but Mtot does not; that is, sand is shifted between the containers before each trial.

Which of the curves gives the tension in the connecting cord (the vertical axis is for tension)?

- 1
- 2
- 3
- 4

**Q.**In the figure shown, find the tension in the string connecting the blocks of mass 2 kg and 3 kg. Take g=10 m/s2

- 10 N
- 12.4 N
- 13.6 N
- 15.2 N