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Question

# A body of mass 5 kg is suspended by the strings making angles 60o and 30o with the horizontal as shown in the figure. Find the tension in the strings. (g=10 m/s2 )

A
T1=25 N & T2=25 N
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B
T1=253 N & T2=25 N
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C
T1=25 N & T2=253 N
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D
T1=253 N & T2=253 N
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Solution

## The correct option is C T1=25 N & T2=25√3 N Taking components of both T1 and T2 along horizontal and vertical direction, we get For horizontal equilibrium of mass 5 kg: T2cos60o=T1cos30o(i) For vertical equilibrium of mass 5 kg T2sin60o+T1sin30o=5g(ii) From equations (i) and (ii) T1=25 N and T2=25√3 N

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