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Question

# A string of length 1 m is fixed at one end and carries a mass of 100 g at the other end. The string makes (2/π) revolutions per second around vertical axis through the fixed end. What is the tension in the string :-

A
1.6 N
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B
0.8 N
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C
3.2 N
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D
2.4 N
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Solution

## The correct option is A 1.6 NEquating forces Tsinθ=m×v×v/r ...(1) Tcosθ=m×g ...(2) ω=2/π×2π=4 rad From 1 and 2 tanθ=v2/rg=ω2r/g sinθ=r tanθ=42×(sinθ)/g sinθ/cosθ=16×sinθ/10 1/cosθ=1/1.6=0.625 ...(3) From (3) T=mg/cosθ=(0.1×10)/(1/1.6) T=1.6 N

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