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Question

# In the figure shown, find the tension in the string connecting the blocks of mass 2 kg and 3 kg. Take g=10 m/s2

A
10 N
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B
12.4 N
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C
13.6 N
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D
15.2 N
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Solution

## The correct option is C 13.6 NConsidering 2 kg and 3 kg masses as a system, we have from the FBDs as f1=μ1(2g)=0.3×20=6 N and, f2=μ2(3g)=0.2×30=6 N Also, equation of force can be written as 5g−T1=5a..........(i) T1−(f1+f2)=5a......(ii) Thus, from eq (i) and (ii) we get 5g−(f1+f2)=10a a=50−(6+6)10=3810=3.8 m/s2 Now, from the FBD of 2 kg mass we get T−f1=2a T=f1+2a=6+2(3.8) ⇒ T=13.6 N

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