A rubber cube of side 5cm has one side fixed while a tangential force equal to 1800N is applied to the opposite face. Find the shearing strain and the lateral displacement of the strained face. Modulus of rigidity for rubber is 2.4×106N/m2.
A
0.3radian,1.5cm
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B
1.2radian,1.225cm
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C
0.72radian,1.96cm
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D
0.98radian,2.25cm
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Solution
The correct option is A0.3radian,1.5cm Given, L=5×10−2m Tangential Force F=1800N Modulus of rigidity η=2.4×106N/m2
As we know, Modulus of rigidity η=Tangential StressShear strain=(FA)θ ⇒Shear strain(θ)=FA×η=1800(5×5×10−4)×2.4×106 =18025×24=310=0.3radian