A runner covers a distance of $270 m e t r e s$ in $30 s e c o n d s$ .
Find his speed in $m / s$

Open in App

Solution

Speed formula:
We know that speed is given in terms of distance covered and time taken as :
$s p e e d = \frac{d i s \tan c e c o v e r e d}{t i m e t a k e n}$
$s p e e d = \frac{270 m}{30 s} = 9 m / s$
Hence, the speed of the runner is $9 m / s$ .

Suggest Corrections

Similar questions

Q. A runner runs a distance 270 m in 30 sec. Find the speed in km/hr?

Anjali swam for $50 s e c o n d s$ at a speed of $4.5 m / s$ . Then, she swam for another $70 s e c o n d s$ at a speed of $1.5 m / s$ . Find the distance covered by anjali in metres.

Q. A long distance runner runs

9

laps of a

400

metre track everyday. His timings (in min) for four consecutive days are

88,

96,

89

and

87

respectively. On an average, how many metres/minute does the runner cover?

Q. The following graph shows the distance covered by runners in 3.8 seconds. Calculate Ahmed's speed in m/s.

Q. What is the speed of a car if it covers a distance of 500 metres in 20 seconds?

Join BYJU'S Learning Program

A runner covers a distance of 270metres in 30seconds. Find his speed in m/s

Speed formula:We know that speed is given in terms of distance covered and time taken as :speed=distancecoveredtimetakenspeed=270m30s=9m/sHence, the speed of the runner is 9m/s.

A runner covers a distance of $270 m e t r e s$ in $30 s e c o n d s$ .
Find his speed in $m / s$

Speed formula:
We know that speed is given in terms of distance covered and time taken as :
$s p e e d = \frac{d i s \tan c e c o v e r e d}{t i m e t a k e n}$
$s p e e d = \frac{270 m}{30 s} = 9 m / s$
Hence, the speed of the runner is $9 m / s$ .