A runs $1 \frac{3}{4}$ times as fast as B. If A gives B a start of 60 m, how far must the winning post be so that A and B might reach it at the same time ?

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Solution

Ratio of the speed of A and B = 7 : 4
3 m are gained by A in a race of 7 m.
60 m are gained by A in a race of $(\frac{7}{3} \times 60) = 140 m$

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A runs 134 times as fast as B. If A gives B a start of 60 m, how far must the winning post be so that A and B might reach it at the same time ?

Ratio of the speed of A and B = 7 : 43 m are gained by A in a race of 7 m.60 m are gained by A in a race of (73×60)=140 m

A runs $1 \frac{3}{4}$ times as fast as B. If A gives B a start of 60 m, how far must the winning post be so that A and B might reach it at the same time ?

Ratio of the speed of A and B = 7 : 4
3 m are gained by A in a race of 7 m.
60 m are gained by A in a race of $(\frac{7}{3} \times 60) = 140 m$