Akshit runs 2.66 times as fast as Bhagwan. If Akshit gives Bhagwan a start of 120 m, how far must the winning post stand so that Akshit and Bhagwan reach it at the same time?

192 m

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200 m

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240 m

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160 m

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250 m

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Solution

The correct option is A
192 m

Ratio of the speeds of Akshit and Bhagwan = $\frac{8}{3} : 1 = 8 : 3$
Thus, in a race of 8 m, Akshit gains 5 m over Bhagwan.
5 m are gained by Akshit in a race of 8 m.
120 m will be gained by Akshit in race of $(\frac{8}{5} \times 120) = 192 m$

$∴$ Winning post is 192 m away from the starting point.

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Akshit runs 2.66 times as fast as Bhagwan. If Akshit gives Bhagwan a start of 120 m, how far must the winning post stand so that Akshit and Bhagwan reach it at the same time?

The correct option is A 192 m Ratio of the speeds of Akshit and Bhagwan = 83:1=8:3 Thus, in a race of 8 m, Akshit gains 5 m over Bhagwan. 5 m are gained by Akshit in a race of 8 m. 120 m will be gained by Akshit in race of (85×120)=192m ∴ Winning post is 192 m away from the starting point.