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Enthalpy of Neutralisation

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Question

A sample of $28$ mL of $H_{2} O_{2} (a q)$ solution required $10$ mL of $0.1 M$ $K M n O_{4} (a q)$ solution for complete reaction in acidic medium. The volume strength of $H_{2} O_{2}$ is:

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Solution

let volume strength of $H_{2} O_{2}$ is x,
No. of equivalents of $H_{2} O_{2} =$ no. of equivalents of $0.1 M K M n O_{4} (a q)$ .
$28 \times \frac{17 x}{5600} \times 17 = 10 \times 0.1 \times \frac{5}{1000}$
or, $x = 1$ .

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