A sample of 500 g dry sand, when poured into a 2 litre capacity cylinder which is partially filled with water, displaces 188 $c m^{3}$ of water. The density of water is $1 g / c m^{3}$ . The specific gravity of the sand is

2.66

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2.52

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2.72

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2.55

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Solution

The correct option is A 2.66
Weight of dry sand (w) = 500 gram

Sand displaced 188 $c m^{3}$ of water .

$S o, v o l u m e o f s a n d = 188 c m^{3}$

$S p e c i f i c g r a v i t y o f s a n d (G) = \frac{(ρ_{d})_{s a n d}}{ρ_{w}}$

$(ρ_{d})_{s a n d} = \frac{500}{188} = 2.659 g r a m / c m^{3}$

$S o, G = (\frac{(ρ_{d})_{s a n d}}{ρ_{w}}) = \frac{2.659}{1} = 2.659 \approx 2.66$

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A sample of 500 g dry sand, when poured into a 2 litre capacity cylinder which is partially filled with water, displaces 188 cm3 of water. The density of water is 1 g/cm3. The specific gravity of the sand is

The correct option is A 2.66Weight of dry sand (w) = 500 gram Sand displaced 188 cm3 of water . So, volume of sand =188 cm3 Specific gravity of sand (G)=(ρd)sandρw (ρd)sand=500188=2.659 gram / cm3 So, G=((ρd)sandρw)=2.6591=2.659≈2.66

A sample of 500 g dry sand, when poured into a 2 litre capacity cylinder which is partially filled with water, displaces 188 $c m^{3}$ of water. The density of water is $1 g / c m^{3}$ . The specific gravity of the sand is