A sample of CaCO3 contains 3.01×1023 ions of Ca2+ and CO2−3. The mass of the sample is:
We know that CaCO3 contains 1 mole of both Ca2+ and CO2−3 ions that is, 6.02×1023 ions of both the ions.
Now, since the number of ions in the question is given to be 3.01×1023 which is half of 6.02×1023, hence, the number of moles will also get halved.
Since we know that moles=Given massMolecular mass
Therefore, 12=Required mass of CaCO3100
Required mass of CaCO3=50g
Hence, option (b) is correct.