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Question

A sample of CaCO3 contains 3.01×1023 ions of Ca2+ and CO23. The mass of the sample is:


A
100 g
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B
50 g
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C
200 g
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D
5 g
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Solution

The correct option is B 50 g

We know that CaCO3 contains 1 mole of both Ca2+ and CO23 ions that is, 6.02×1023 ions of both the ions.

Now, since the number of ions in the question is given to be 3.01×1023 which is half of 6.02×1023, hence, the number of moles will also get halved.

Since we know that moles=Given massMolecular mass

Therefore, 12=Required mass of CaCO3100

Required mass of CaCO3=50g

Hence, option (b) is correct.


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