Question

A sample of gas occupies $1.50L$ at ${25}^{o}C$. If the temperature is raised to ${60}^{o}C$, what is the new volume of the gas if pressure remains constant?

Answer 1

According to Chares law $\frac{V2}{V1}=\frac{T2}{T1}$

Given $V_1$=1.50 L

T1=25 degree celsius=298 K

T2=60 degree celsius=333 K

$V_2=\frac{T2}{T1}\times V_1=\frac{333\times 1.5}{298}=1.67L$