A sample of HCl is placed in an electric field of 2.5×104NC−1. The dipole moment of HCl is 3.4×10−30Cm. Find the maximum torque that can act on a molecule.
A
7.6×10−26Nm
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B
4.3×10−26Nm
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C
6.5×10−26Nm
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D
8.5×10−26Nm
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Solution
The correct option is D8.5×10−26Nm Torque ,→τ=→p×→E=pEsinθ ∴τmax=pE =3.4×10−30×2.5×104 =8.5×10−26Nm