A Sample of mixture of CaCl2 and NaCl weighing 4.44g was treated to precipitate all the Ca as CaCO3, which was then heated and quantitatively converted to 1.12g of CaO. (Atomic weight: Ca= 40, Na= 23, Cl= 35.5)
A
Mixture contains 50% NaCl
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Mixture contains 60% CaCl2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Mass of CaCl2 is 2.22g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
Mass of CaCl2 is 1.11g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C Mass of CaCl2 is 2.22g Balanced reaction: CaCO30.02mole△−→CO2+CaO0.02mole
CaCl20.02moleNa2CO3−−−−−→CaCO30.02mole
mass of CaCl2 present in mixture =0.02×111=2.22g, which is %50 of the total mass, rest being `NaCl`