A sample of pure P Cl 5 was introduced into an evacuated vessel at 473 K- After equilibrium was attained- concentration of PCl5 was found to be 0-5 - 10-1 molL -1-If valueof K c is 8-3 - 10-3- what are the concentrations of P Cl 3 and Cl 2 at equilibrium- P Cl 5 g - P Cl 3 g - Cl 2 g

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Byju's Answer

Standard XII

Chemistry

Derivation of Kp and Kc

A sample of p...

Question

A sample of pure $P C l_{5}$ was introduced into an evacuated vessel at 473 K. After equilibrium was attained, concentration of PCl_5 was found to be $0.5 \times 10^{- 1} m o l L^{- 1} . I f v a l u e o f K_{c} i s 8.3 \times 10^{- 3}$ , what are the concentrations of $P C l_{3}$ and $C l_{2}$ at equilibrium?\\
$P C l_{5} (g) \leftrightarrow P C l_{3} (g) + C l_{2} (g)$

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Solution

Let the concentrations of both $P C l_{3}$ and $C l_{2}$ at equilibrium be $x m o l L^{- 1}$ . The given reaction is:
$\begin{matrix} P C l_{5 (g)} & \leftrightarrow & P C l_{3 (g)} & + & C l_{2 (g)} A T e q u i l i b r i u m & 0.5 \times 10^{- 1} m o l L^{- 1} & z m o l L^{- 1} & x m o l L^{- 1} \end{matrix}$
It is given that the value of equilibrium constant. $K_{c}$ is $8.3 \times 1^{- 3}$
Now we can write the expression for equilibrium as:
$\frac{[P C l_{2}] [C l_{2}]}{[P C l_{5}]} = K_{c} \Rightarrow \frac{x \times x}{0.5 \times 10^{- 1}} = 8.3 \times 10^{- 3} \Rightarrow x^{2} = 4.05 \times 10^{- 4} \Rightarrow x = 2.04 \times 10^{- 2} = 0.0204 = 0.02 (a p p r o x i m a t e l y)$
Therefore, at equilibrium,
$[P C l_{3}] = [C L_{2}] = 0.02 m o l L^{- 1}$

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Similar questions

Q. A sample of pure

{P C l}_{5}

was introduced into an evacuated vessel at 473 K. After equilibrium was attained, concentration of

{P C l}_{5}

was found to be

0.5 \times 10^{- 1} m o l L^{- 1}

. If value of

K_{c}

8.3 \times 10^{- 3}

, what are the concentrations of

{P C l}_{3}

and

{C l}_{2}

at equilibrium?

{P C l}_{5} (g) ⇌ {P C l}_{3} (g) + {C l}_{2} (g)

A sample of pure PCl₅ was introduced into an evacuated vessel at 473 K. After equilibrium was attained, concentration of PCl₅ was found to be 0.5 × 10^–1 mol L^–1. If value of K_c is 8.3 × 10^–3, what are the concentrations of PCl₃ and Cl₂ at equilibrium?