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Question

A sample of pure PCl5 was introduced into an evacuated vessel at 473 K. After equilibrium was attained, concentration of PCl_5 was found to be 0.5×101molL1.IfvalueofKcis8.3×103, what are the concentrations of PCl3 and Cl2 at equilibrium?\\
PCl5(g)PCl3(g)+Cl2(g)

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Solution

Let the concentrations of both PCl3 and Cl2 at equilibrium be x molL1. The given reaction is:
PCl5(g)PCl3(g)+Cl2(g)AT equilibrium0.5×101mol L1z mol L1x mol L1
It is given that the value of equilibrium constant. Kc is 8.3×13
Now we can write the expression for equilibrium as:
[PCl2][Cl2][PCl5]=Kcx×x0.5×101=8.3×103x2=4.05×104x=2.04×102=0.0204=0.02 (approximately)
Therefore, at equilibrium,
[PCl3]=[CL2]=0.02 mol L1


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