Question

A sample of sulfur dioxide occupies a volume of $652mL$ at ${40}^{\circ }C$ and $720mmHg$. What volume will the sulfur dioxide occupy at STP?

Answer 1

We have

1 mm Hg = 0.0013 atm

So, $P=720mmHg=0.94atm$

and 652 ml =0.652 L, $T={40}^{0}C=313K$

$PV=nRT$

putting the values, we have

$0.94\times 0.652=n\times 0.0821\times 313$

n = 0.023 moles

So, At STP, we have,

volume of 1 mole of gas = 22.4 L

so, volume of 0.023 mole of gas = $22.4\times 0.023=0.515L$ or 515 ml