Volume occupies by 4.4 grams of carbon dioxide at STP is :

2.24

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22.4

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224

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2.24 \times 10^{3}

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Solution

The correct option is B 2.24
Volume occupied by the as $= V = ?; S T P \Rightarrow$ temperature of the gas $= T = 273 K$ and

Mass of the gas $= m = 4.4 g$

Pressure exerted by the gas $= p = 1 a t m$

$P V = n R T$

$\Rightarrow P V = \frac{m}{W} R T . . . . . (1)$
where 'W' is the molecular weight of $C O_{2} (44)$
Substituting the values from the data in the equation (1), we get

$\Rightarrow 1 \times V = \frac{4.4}{44} \times 0.0821 \times 273$

$\Rightarrow V = \frac{1}{10} \times 22.4 = 2.24 L$

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Similar questions

4.4

S T P

4.4

2.24

4.4 g of a gas at STP occupies a volume of 2.24 L. The gas can be:

4.4 g

2.24 L

C O_{2}

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