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Question

# A sample of water gas has a composition by volume of 50% H2, 45% CO and 5% CO2. Calculate the volume in litres at STP at which the water gas on treatment with excess of steam will produce 5 L of H2. The equation for the reaction is: CO+H2O→CO2+H2

A
5.26 L
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B
2.33 L
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C
5.00 L
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D
7.20 L
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Solution

## The correct option is A 5.26 LGiven information: Composition of the water gas is 50% H2, 45% CO and 5% CO2 Let the volume of water gas be x L. Then, volume of H2 = 0.5x L volume of CO =0.45x L volume of CO2 = 0.05x L Final volume of H2 after reaction with steam = 5 L CO in water gas reacts with steam to produce H2 according to the equation, CO+H2O→CO2+H2 Applying Gay Lussac's law, volume of H2 formed = volume of CO consumed = 0.45x L Final volume of H2 = (volume of H2 present initially + volume H2 formed from CO) ⇒5 L=0.5x L+0.45x L ⇒x=5.26 L

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