wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

A sample space S is given as S = {1, 2, 3, 4, 5,6, 7}
Following events are described for this sample space.
Event X = {1,2,3}
Y = {3,4,5}
Z = {5,6,}
Events X , Y and Z are not exhaustive events because event X and event Y have an element in common

A
True
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
False
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is B False
Look for events to be exhaustive there is only one condition that their union should give sample space. No such condition that they should have no element in common exists. Yes the events are not exhaustive because their union does not give the sample space, not because they have elements in common. So the reason given in the statement is wrong.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon