A satellite is orbiting earth at a distance of 42000 km in a circular orbit. It completes one revolution in 24 hours. Calculate its linear speed.

10990 km/hr

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10890 km/hr

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11000 km/hr

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11880 km/hr

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Solution

The correct option is A
10990 km/hr

Given, radius, $r = 42000 k m$ and time taken, $= 24 h o u r s$ .
Total distance traveled by the satellite = $2 π r$
$= 2 \times 3.14 \times 42000 = 263760 k m$

Linear speed $= \frac{d i s t a n c e}{t i m e}$ $= \frac{263760}{24}$ $= 10990 k m p h$

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A satellite is orbiting earth at a distance of 42000 km in a circular orbit. It completes one revolution in 24 hours. Calculate its linear speed.

The correct option is A 10990 km/hr Given, radius,r = 42000 kmand time taken,=24hours. Total distance traveled by the satellite = 2πr =2×3.14×42000=263760 km Linear speed =distancetime =26376024 =10990 kmph

The correct option is A
10990 km/hr

Given, radius, $r = 42000 k m$ and time taken, $= 24 h o u r s$ .
Total distance traveled by the satellite = $2 π r$
$= 2 \times 3.14 \times 42000 = 263760 k m$

Linear speed $= \frac{d i s t a n c e}{t i m e}$ $= \frac{263760}{24}$ $= 10990 k m p h$