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Question

A satellite is placed in a circular orbit around earth at such a height that it always remains stationary with respect of earth surface. In such case, its height from the earth surface is:

A
32000 km
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B
36000 km
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C
6400 km
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D
4800 km
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Solution

The correct option is A 36000 km
As the satellite always remains stationary w.r.t earth surface, thus its time period revolution is equal to time period of rotation of earth i.e 24 hrs

Time period of satellite T=2πr3gR2 where R=6400 km=6.4×106 m

24×3600 =2πr39.8(6.4×106)2
OR r3401.408×1012=1.89×108 r3=76×1021
r=42400 km
Thus height of satellite above earth surface h=424006400=36000 km

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