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Question

# A satellite is revolving round the earth in circular orbit at some height above surface of earth. It takes 5.26× 103 seconds to complete a revolution while its centripetal acceleration is 9.92 m/s2 . Height of satellite above surface of earth is (Radius of earth 6.37×106 m)

A

70 km

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B

120 km

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C

170 km

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D

220 km

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Solution

## The correct option is C 170 km Centripetal acceleration (ac)=v2r and T=2πrv From equation (i) and (ii) r=acT24π2⇒R+h=9.32×(5.26×103)4×π2 h=6.53×106−R=6.53×106−6.37×106=160×103m=160km≈170km

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