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Question

# A remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25×105m above the surface of earth . If earth's radius is 6.38×106 m and g=9.8ms−2, then the orbital speed of the satellite is

A
6.67Kms1
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B
7.92Kms1
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C
8.56Kms1
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D
9.13Kms1
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Solution

## The correct option is B 7.92Kms1Given, Radius of earth, Re=6.38×108m Height from earth surface, h=0.25×105m Distance from earth center, r=Re+h=6.38×106+0.25×105=6405×103m Orbital speed of satellite, v=√GMr=√gr=√9.8×6405×103=7.92km/s Hence, orbital speed is 7.92kms−1

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