Question

A science student is riding on a flat car roof train travelling a straight horizontal track at a constant speed of 10 mps. The student throws a ball into the air along a path that he just to make an initial angle 60 degrees with the horizontal and to be in line with the track the student's professor who is standing on the ground nearby, observe the ball to rise. Vertically how high does the ball rise?

Answer 1

Given,

Initial velocity = u = 10 m/s

Angle of projection = θ=60o\theta = 60^oθ=60o

We know that the height of the projectile is given by,

$H=\frac{u^{2}si{n}^2\theta }{2g}$

$H=\frac{{\left(10\right)}^2\times si{n}^2\left({60}^o\right)}{2\times 9.8}=\frac{100\times 3}{2\times 9.8\times 4}=\frac{300}{78.4}$

$H=3.83m$.