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Question

A screw gauge gives the following reading when used to measure the diameter of a wire.
Main scale reading : 0 mm
Circular scale reading : 52 divisions
Given that 1 mm on main scale corresponds to 100 divisions of the circular scale. The diameter of wire from the above data is :

A
0.52cm
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B
0.052cm
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C
0.026cm
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D
0.005cm
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Solution

The correct option is B 0.052cm
Here, pitch of the screw gauge, p=1 mm
Number of circular divisions, n=100
Thus, least count LC=p/n=1/100=0.01 mm=0.001 cm
Diameter of the wire =MSR+(CSR×LC)=0+(52×0.001cm)=0.052 cm

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