Question

A screw gauge has the least count of $0.01\text{mm}$ and there are $\text{50}$ divisions in its circular scale. The pitch of the screw gauge is :

• A. $0.5\text{mm}$
• B. $1.0\text{mm}$
• C. $0.01\text{mm}$
• D. $0.15\text{mm}$

Answer 1

The correct option is A $0.5\text{mm}$

Given,
$\text{Least Count}=0.01\text{mm}$
$\text{No of division}=50$

$\text{Least Count}$ $=\frac{\text{Pitch}}{\text{No of division on circular scale}}$

$\Rightarrow \text{Pitch}$$=\text{Least Count}\times \text{No of division on circular scale}$
$\Rightarrow \text{Pitch}=\text{0.01}$$\times$$\text{50}$
$\Rightarrow \text{Pitch}=0.5\text{mm}$