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Question

A scuba diver and a swimmer are swimming in the ocean. The diver, at the depth of 50 m is required to take precautions against high pressure at depths.
Given: ρwater=1000 kg/m3, g=10 m/s2, Po=105 Pa
1. Find the pressure difference between them.
2. Find the total pressure felt by the diver.

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Solution

1.
Pressure difference between two depths in a fluid is given by:
P2P1=ρg(h2h1)
P2P1=1000×10×(500)
P2P1=5×105 Pa

2. Total pressure felt by the diver is:
P=Po+ρgh
P=105+5×105
P=6×105 Pa

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