Question

A series resonant LCR circuit has a quality factor (Q-factor) = 0.4. If R 2 k$\Omega$, C = 0.1 $\mu$F, then the value of Inductance is

• A. 0.1 H
• B. 0.064 H
• C. 2 H
• D. 5 H

Answer 1

The correct option is B 0.064 H

Quality factor $Q=\frac{1}{R}\sqrt{\frac{L}{C}}or\frac{L}{C}=(QR{)}^2$
Here, $Q=0.4,R=2K\Omega =2\times {10}^3\omega$

$C=0.1\mu F=0.1\times {10}^{-6}F$

$\therefore L=(QR{)}^{2}C$

$\therefore L=(0.4\times 2\times {10}^3{)}^2\times 0.1\times {10}^{-6}=0.064H$