A series LCR circuit connected across 200 V- 60 Hz source- It consists of a capacitor of capacitive reactance 30 - a non-inductive resistor of 40 - and an ideal inductor of inductive reactance 90 - as shown in the figure- The average power dissipated across the inductor is - -0-77 Mark-

We know that, average power, P_avg = V_rmsI_rmscosϕ nbsp; For an ideal inductor, cosϕ= 0 [∵ϕ = 90^∘] ⇒ P_avg = 0 ...

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Standard XII

Physics

Reactance

A series LCR ...

Question

A series $LCR$ circuit connected across $(200 V, 60 Hz)$ source. It consists of a capacitor of capacitive reactance $30 Ω$ , a non-inductive resistor of $40 Ω$ and an ideal inductor of inductive reactance $90 Ω$ as shown in the figure. The average power dissipated across the inductor is -

$[$ 0.77 Mark $]$

160 W

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50 W

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240 W

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Zero

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Solution

The correct option is D Zero
We know that, average power,

$P_{a v g} = V_{r m s} I_{r m s} cos ϕ$

For an ideal inductor, $cos ϕ = 0$ $[∵ ϕ = 90^{\circ}]$

$\Rightarrow P_{a v g} = 0$

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The correct option is D ZeroWe know that, average power, Pavg=VrmsIrmscosϕ For an ideal inductor, cosϕ=0 [∵ϕ=90∘] ⇒Pavg=0

The correct option is D Zero
We know that, average power,

$P_{a v g} = V_{r m s} I_{r m s} cos ϕ$

For an ideal inductor, $cos ϕ = 0$ $[∵ ϕ = 90^{\circ}]$

$\Rightarrow P_{a v g} = 0$