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Question

A set of n equal Resistances of value R each are connected in series to a battery of emf E, and internal Resistance R, then the current drawn is I. Now when the n resistors are connected in parallel to same battery, then current drawn is I, Find the  relation between I and I ?
  1. I=I
  2. I=nI
  3. I=n2I
  4. I=n2I


Solution

The correct option is B I=nI

Rseries=nR+R=(n+1)R

I=vR(n+1)

Rparllel=R+Rn=((n+1)Rn)

I=V.n(n+1)R

II=1nI=nI

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