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Standard XII

Physics

Energy of a Capacitor

A Battery of ...

Question

A Battery of emf $E$ (internal resistance = 0) is connected with $n$ resistors in parallel having equal resistance $R$ , then $I$ vs $n$ graph is:

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Solution

The correct option is B
As in the battery, internal resistance is zero, so we can say $E = V$ .

$R_{e q} = \frac{R}{n} I = \frac{V . n}{R} \Rightarrow I \propto n$

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A Battery of emf E (internal resistance = 0) is connected with n resistors in parallel having equal resistance R, then I vs n graph is:

The correct option is B As in the battery, internal resistance is zero, so we can say E=V. Req=RnI=V.nR⇒I∝n

A Battery of emf $E$ (internal resistance = 0) is connected with $n$ resistors in parallel having equal resistance $R$ , then $I$ vs $n$ graph is:

The correct option is B
As in the battery, internal resistance is zero, so we can say $E = V$ .

$R_{e q} = \frac{R}{n} I = \frac{V . n}{R} \Rightarrow I \propto n$