A shell is fired from cannon with a velocity V at an angle θ with the horizontal direction. At the highest point in its path, it explodes into two pieces of equal masses. One of the pieces retraces its path to the cannon. The speed of the other piece immediately after the explosion is
Figure shown depicts the situation described
(Pi)x=2mVCosθ^i
Now at the highest point of its trajectory, if other mass (i.e., m) retraces its path back to the initial point.
Then its required velocity (which is horizontal towards left).
V2=−v cosθ^i
Let velocity of other mass be v1
As there is no force by any external means in horizontal direction, its Linear momentum in this direction is conserved.
⇒ 2 mv cosθ^i= − mv cos θ ^i+mv1
V1=3 V cos θ ^i